Gametes, Genotypes, and Phenotypes
Sometimes, it is easier to determine how many possible phenotypes, genotypes, and gametes are available from the crossing of two parents. The equations are as follows:
![]()
N is the number of heterozygous gene pairs. For instance, if a genotype is AaBbCc, n will be 3. However, if the genotype is AABbCC, the n is 1.
When analyzing two parents, it is easier to determine how many possible phenotypic and genotypic combinations of each gene pair, and then multiply them all together.
![]()
All of this can be figured if there is no linkage.
- Continue to Gamete Problems
- Return to Main Menu
![]()
© 1998-2009 NAGRP - U. S. Pig Genome Research Coordination Program.
Contact: The NAGRP Bioinformatics Project TeamNovember 24, 2009 (Tuesday)